Ok. I have this problem for homework, I soluble it and will post it here, such as my next problems and programs.

Natural numbers are written one by one in infinity array: 12345678910111213... For entered number N by keyboard find the number which is on that position.

Example: If you type 16, the number which need to be write is 1.

123456789101112**[u]1[u]**3

I test it for n=[1,100] and it works. Just to note that if you work with big numbers you need to change the type of array from **int** to **long**, coz you will get overflow.

```
int brojCifri(int broj){
int cifri = 0;
while(broj != 0){
cifri++;
broj /= 10;
}
return cifri;
}
int najdiCifra(int n){
if(n<=9) return n;
bool done = false;
int cifri = 11, i = 10;
while(!done){
if(cifri >= n){
done = true;
}
else{
i++;
cifri += brojCifri(i);
}
}
if(done){
while(i && cifri>n){
i /= 10;
cifri--;
}
return i%10;
}
return -1;
}
```

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