Date Sort

By vaseline28 on Nov 11, 2009

    This script sorts a list of dates into order - old -> new
    Can be used for dates which do not exist yet!

    To use this simply use the code:

        ago(VAR1, new Array(DATE1), new Array(DATE2));

    Adding as many dates within arrays and seperated by commas as you like.

        VAR1 = the date which you want the script to return:
            e.g. 0 = oldest date
                   1 = second oldest date
                   2 = third oldest date

        DATE1 = must be in the following format within the array:

            new Array(1, 2, 3, 4, 5)

            1 = minutes of the hour
            2 = hours of the day
            3 = date of the month
            4 = month of the year
            5 = year

        You can have as many dates as you like.

    Example of code use:

        alert(ago(1, new Array(1, 12, 29, 0, 2004), new Array(13,4,29,0,2005), new Array(24, 15, 13, 11, 9011), new Array(25, 11, 16, 10, 1456)));
function ago()
    var x = 0; date = new Array(); y = 0; returns = new Array();

    while (x < arguments.length)
        if (typeof(arguments[x]) != "number")

            var curArgument = arguments[x];

            date[x] = new Date();



        return a - b;

    return (typeof(arguments[0]) == "number") ? date[arguments[0]] : date;


Sign in to comment.
Korvin   -  Mar 02, 2010

looks good.

ugh java, i cant really judgejavascript.

vaseline28   -  Nov 12, 2009

I would usually either cut out the time section and use it to work out who's older or I would use it to order a group of events, e.g.:

User1 Logged In
User2 Posted A Comment

As a rough example. To be honest, I was really just making it for fun and to experiment with not limited variables passed to the function.

Hawkee   -  Nov 11, 2009

Seems simple enough, what do you use it for?

Ghost-writer   -  Nov 11, 2009

ugh java, i cant really judge.

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