@ChunkieMonkey

in my opinion your declaring Z as your 1st number and X as 2nd number but your condition said Z=X*Y.. better change your inputs very well..that's all.

and for you Zmodem

include

using namespace std;

int main()
{
int num1,num2,product;
cout << "Enter first number: ";
cin >> num1;
cout << "Enter second number: ";
cin >> num2;
product = num1 * num2;
cout << "The product is: " << product << endl;
system("pause");
return 0;
}

better change it dude..

int num1,num2,product;>>> to double num1,num2,product;

cause integers are declaring only a single variable..

lol @ him saying this actually works. need to rearrange those variables.

DiGiTaL: Good point. Get rid of those nasty leftovers and ignore that enter key.

   cout<<"The product is"<<num1*num2<<endl;
   cin.ignore();

Just like to toss in my two cents, so bear with me.

A major contradiction in programming is using meaningful variable names, which, in this case, make no sense at all. Why not use names like: num1, num2 & product? Anyways, I'm using Visual Studio 2008 and when I compile this code, I always get a product response of:

The two you entered multiplied is 0

No matter what numbers I've entered, the product is always 0. The reason for this is quite obvious, as everyone has already stated that your variables are all mixed up and in the wrong spot. In any case, something to the correct deter would be:

#include <iostream>
using namespace std;

int main()
{
  int num1,num2,product;
  cout << "Enter first number: ";
  cin >> num1;
  cout << "Enter second number: ";
  cin >> num2;
  product = num1 * num2;
  cout << "The product is: " << product << endl;
  system("pause");
  return 0;
}

Variable scoping problem here,

Why make x,y & z a global variable when you only need it within the function. You might as well do this in C not C++.

//My compiler is dev c++
//Second snippet made

#include <iostream>
using namespace std;
int x,y,z;
int main(){
    cout << "Type a number. ";
    cin >> z;
    cout << "Type another. ";
    cin >> x;
    z = x*y;
    cout << "The two you entered multiplied is " << z << "\n";
    system("pause");
}

Cleaner, Easier, Nicer

Chunkie the problem is you aren't requesting y from the user, you're requesting x and z.

Actually it does work, I tested it on my compiler before I uploaded it. if you ran it through a compiler it asks you for a number, then another. The user of the script sets the values of the variable x and y.

ChunkieMonkey
Comments: 103

C++ Snippet: C++ variable use
Posted on Aug 26, 2008 12:31 am
Hello people lookin at nemisis' annoying comment script. and this is a simple variable use w/e

Annouying huh so ignore me or haltdef it;p

yea should be y =z*x;

uh,

    cout << "Type a number. ";
    cin >> z;

    cout << "Type another. ";
    cin >> x;

    z = x*y;

that's just going to do

z = x*

as y isn't being set

Hello people lookin at nemisis' annoying comment script. and this is a simple variable use w/e